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The following data refers to a test on an axial flow compressor. Atmospheric temperature an pressure at inlet are 18°C and I bar. Total head temperature in delivery pipe is 165°C. Tota head pressure in delivery pipe is 3.5 bar. Static pressure in delivery pipe is 3 bar. Adiabat index (y) or ratio of specific heats of flowing gas = 1.4 Calculate (a) total head isentropic efficiency. (b) Polytropic efficiency, and (c) air Velocity delivery pipe.
Given data: Inlet temperature, T, = 18° C = 291 K Inlet pressure, P1= 1 bar Outlet temperature, T₂ =165° C = 438 K Outlet pressure, P₂ = 3.5 bar Solution: (a) Total head isentropic efficiency Calculated the enthalpy of air at T1, and P1 using online calculator h1=291.544 kJ/kg Calculated the enthalpRead more
Given data:
Inlet temperature, T, = 18° C = 291 K
Inlet pressure, P1= 1 bar
Outlet temperature, T₂ =165° C = 438 K
Outlet pressure, P₂ = 3.5 bar
Solution:
(a) Total head isentropic efficiency
Calculated the enthalpy of air at T1, and P1 using online calculator
h1=291.544 kJ/kg
Calculated the enthalpy of air at T1 and P2, from using calculator
h₂ = 290.9465 kJ/kg
Calculated the enthalpy of air at T₂ and P2 using online calculator
h3 =443.36 kJ/kg
Calculated the enthalpy of air at T2, and P1 using online calculator
h4 = 440.0875 kJ/kg
Calculating the isentropic efficiency of the compressor,
ηIsentropic = (h1-h2/h4-1)x100_______________(1)
Substituting the values in the above equation (1).
ηIsentropic= (291.544-290.9456 /443.36-440.0875)× 100
ηIsentropic = 18.285%
Hence, the isentropic efficiency of the compressor is 18.285%
(b) Polytropic efficiency
Polytrophic path coefficient,
n = [1-(438/291)/(3.5/1)^-1
n = 1.754
ηpoly = (1.4-1/1.4)/(1.754-1/1.754) × 100
ηpoly = 66.464%
Here, 1.4 is the ratio of specific heat of the air.
Hence, the polytrophic efficiency of the compressor is 66.464%
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